WebMay 18, 2012 · Get common items from list1 and list2 (eg. {"2", "3", "4"}) Get different items list1 and list2 (eg. {"1", "5", "6"}) So I've tried with LINQ and - var listDiff = list1.Except (list2); //This gets the desire result for different items But, var listCommon = list1.Intersect (list2); //This doesn't give me desire result. WebAug 27, 2012 · 2 This works because GetHashCode always return 0, and the x.Contains (y) y.Contains (x) check. Another not-so-hacky solution is to use a Where in combination with Any IEnumerable intersect = props.Where (p => ids.Any (i => p.Contains (i)));
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WebApr 25, 2010 · The simplest, most naive solution is if you have two elements of size n, you iterate over one list and compare it to every item in the second list. Solution: O (n 2) But of course you can do much better. Now, if you have a HashSet (or other near-O (1)) data structure available then this is what you can do: Iterate over one list. WebMar 28, 2013 · The hashset-based solution gives O (n) performance which is pretty much as good as it gets. The next best thing would be to sort the two lists and then iterate linearly in lock-step over the two lists, selecting the common elements, which yeilds O (nlogn) performance. Share Improve this answer Follow edited Mar 28, 2013 at 20:31 egrunin
WebDec 15, 2010 · I have two lists List a = new List (); List b = new List (); Now i want to iterate through the elements of both list. I could do that by writing a foreach loop for each list. But is it also possible to do something like that? foreach (object o in a, b) { o.DoSomething (); }WebThe change needed is to specify the generic type parameter of the Aggregate method on the last line like below: var intersection = listOfLists.Aggregate> ( (previousList, nextList) => previousList.Intersect (nextList) ).ToList (); Thanks, I just tried that out and it works!WebJan 14, 2015 · You could use Distinct to fix this, or build a set of site IDs: var siteIds = new HashSet (lstEmps.Select (emp => emp.SiteId)); var products = lstProds.Where (product => siteIds.Contains (product.SiteId)); That's assuming SiteId is an int - if it's an anonymous type or something similar, you may want an extra extension method:WebMar 11, 2024 · Some types of query operations in C#, such as Except, Distinct, Union, and Concat, can only be expressed in method-based syntax. Compiling the Code Create a …WebJan 4, 2012 · If you sort the two lists and then return the SequenceEqual method you can do it all in three lines of code. SequenceEqual returns whether or not two Lists have the …WebOct 9, 2012 · 5. The extra 1 means you can't use Intersect because it returns a set. Here's some code that does what you need: var list1 = new List () { 1, 1, 1, 2, 3 }; var list2 = …WebJun 22, 2024 · C program to find common values from two or more Lists - Create more than one list −// two lists var list1 = new List{3, 4}; var list2 = new List{1, 2, 3};Now, use the Intersect() method to get the common values −var res = list1.Intersect(list2);The following is the complete code −Example Live Demousing System.Collections.Generic; …WebThis post will discuss how to find common items across multiple lists in C#. 1. Using Enumerable.Intersect () Method. The standard solution to find the set intersection of … WebJan 15, 2024 · A simple solution is to first find intersection of two arrays and store the intersection in a temporary array, then find the intersection of third array and temporary array. Time complexity of this solution is O(n1 + n2 + n3) where n1, n2 and n3 are sizes of ar1[], ar2[] and ar3[] respectively. The above solution requires extra space and two …
WebThis post will discuss how to find common items across multiple lists in C#. 1. Using Enumerable.Intersect () Method. The standard solution to find the set intersection of … WebSep 29, 2009 · You can get ahead by sorting the shorted list first, then using List.BinarySearch () to search it. Sorting is O (n * log (n)), comparing is O (m * log (n)). If …
WebHere’s a simple post that shows how to list common elements between two List. Use the Enumerable.Intersect method C# class Program { static void Main ( string [] …
WebWhat is the easiest way to compare the elements of two lists say A and B with one another, and add the elements which are present in B to A only if they are not present in A? To illustrate, Take list A = {1,2,3} list B = {3,4,5} So after the operation AUB I … don\u0027t know what to do gifWebJun 20, 2024 · C program to print all the common elements of two lists - Firstly create the two lists −List list1 = new List() {40, 20, 60, 3, 55}; List list2 = new List() {20, 70, 55, … don\\u0027t know what to do blackpinkWeb4 Answers Sorted by: 52 It sounds like you are trying to find all instances of ObjectB which have a code value present in any of the List values. If so try the following List listA = ...; List listB = ...; var all = listB.Where (b => listA.Any (a => a.code == b.code)); Share Improve this answer Follow don\u0027t know what to do百度云WebJul 24, 2016 · Introduction: This code snippet is Find the common elements in 2 arrays using C#. Code using System; using System.Linq; public class Program { public static void Main () { int[] array1 = {1, 4, 2, 8, 7}; int[] array2 = {7, 5, 9, 1, 0, 2, 6}; // Call Intersect extension method. var intersect = array1.Intersect (array2); don\u0027t know what to do blackpink meaningWebMar 11, 2024 · Some types of query operations in C#, such as Except, Distinct, Union, and Concat, can only be expressed in method-based syntax. Compiling the Code Create a … don\u0027t know what to do blackpink下载WebMar 7, 2024 · The collection you created uses the List type. This type stores sequences of elements. You specify the type of the elements between the angle brackets. One … don\u0027t know what to do with fileWebMar 29, 2024 · This works if your objects in the two lists are the same (the same object reference). If they are only equal, but not the same, consider overriding the Equals operator of the type of the objects in your sets, or use an alternative LINQ expression, such as. IEnumerable set3 = set1.Where((item) => !set2.Any((item2) => … don\u0027t know what to say emoji